(3x - 7) ( x+ 1) < x ( x +3)

Question

Solve

Answer 1

(3x - 7) ( x+ 1) < x ( x +3)
3x^2 - 4x - 7 < x^2 + 3x
2x^2 - 7x - 7 < 0

Aside: y = 2x^2 - 7x - 7 would be a parabola opening upwards, so we want
to find where the parabola lies below the x-axis

for 2x^2 - 7x - 7 = 0
x = (7 ± √105)/4

(7 - √105)/4 < x < (7+√105)/4