(〖3x〗^4/〖6x〗^3 )2

I'm having some trouble solving this. In the numerator is 3x to the 4th. In the denominator is 6x to the 3rd. All of that is in a bracket and it's all squared.

Do I have to first subtract the exponents, 4 - 3 and then multiply by the 2 exponent? I'm a little lost here.

Thank you.

1 answer

The simplification process starts
inside the expression:

((3x)^4/(6x)^3)^2 =
(81x^4/216x^3)^2 = (3x/8)^2 = 9x^2/64.
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