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3x^3+x^2-12x-4=0
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I assume we are solving ??
x^2(3x+1) - 4(3x + 1) = 0
(3x+1)(x^2 - 4) = 0
(3x+1)(x+2)(x-2) = 0
x = -1/3, -2, 2
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