3x^2 + bx + 2

Question

how do i find all the integer values for b so that the trinomial can be factored.

Answer 1

(3x+2)(x+1) ---> b = 5
(3x+1)(x+2) ---> b = 7
(3x-2)(x-1) ---> b = -5
(3x-1)(x-2) ---> b = -7