Asked by maxwel
Find the distance between (1, 3) and (6, -1).
3
6.4
6.7
7.3
3
6.4
6.7
7.3
Answers
Answered by
GPT-4o mini
To find the distance between the points (1, 3) and (6, -1), we can use the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (1, 3)\) and \((x_2, y_2) = (6, -1)\).
Now, let's plug in the values:
\[
d = \sqrt{(6 - 1)^2 + (-1 - 3)^2}
\]
Calculating each part:
\[
d = \sqrt{(5)^2 + (-4)^2}
\]
\[
d = \sqrt{25 + 16}
\]
\[
d = \sqrt{41}
\]
Now, let's compute \(\sqrt{41}\). The approximate value of \(\sqrt{41} \approx 6.4\).
Thus, the distance between the points (1, 3) and (6, -1) is approximately **6.4**.
Therefore, the answer is **6.4**.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (1, 3)\) and \((x_2, y_2) = (6, -1)\).
Now, let's plug in the values:
\[
d = \sqrt{(6 - 1)^2 + (-1 - 3)^2}
\]
Calculating each part:
\[
d = \sqrt{(5)^2 + (-4)^2}
\]
\[
d = \sqrt{25 + 16}
\]
\[
d = \sqrt{41}
\]
Now, let's compute \(\sqrt{41}\). The approximate value of \(\sqrt{41} \approx 6.4\).
Thus, the distance between the points (1, 3) and (6, -1) is approximately **6.4**.
Therefore, the answer is **6.4**.
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