Question

Find the distance of AB (D), A= (12,4) B=(0,11) Round to the nearest tenth

Answer 1

To find the distance \( D \) between the points \( A(12, 4) \) and \( B(0, 11) \), we can use the distance formula:

\[
D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Here, \( (x_1, y_1) = (12, 4) \) and \( (x_2, y_2) = (0, 11) \).

Substituting in the values:

\[
D = \sqrt{(0 - 12)^2 + (11 - 4)^2}
\]

Calculating the differences:

\[
D = \sqrt{(-12)^2 + (7)^2}
\]

Calculating the squares:

\[
D = \sqrt{144 + 49}
\]

Adding the squares:

\[
D = \sqrt{193}
\]

Now, we can approximate the square root of 193.

Calculating \( \sqrt{193} \):

\[
\sqrt{193} \approx 13.889
\]

Rounding to the nearest tenth:

\[
D \approx 13.9
\]

Thus, the distance \( D \) between points \( A \) and \( B \) rounded to the nearest tenth is \( \boxed{13.9} \).