Question

How many moles of carbon monoxide are needed to react with 4.80 g of oxygen gas to produce carbon dioxide? 2CO + O2 --> 2CO2.
Responses

9.6 mol
9.6 mol

0.3 mol
0.3 mol

32 mol
32 mol

8.4 mol

Answer 1

To determine the number of moles of carbon monoxide (CO) needed to react with 4.80 g of oxygen gas (O₂) to produce carbon dioxide (CO₂) based on the balanced reaction equation:

\[ 2CO + O_2 \rightarrow 2CO_2 \]

First, let's calculate the number of moles of oxygen gas:

1. **Calculate the molar mass of O₂:**
- The molar mass of oxygen (O) is approximately 16.00 g/mol.
- Therefore, the molar mass of O₂ (which has 2 O atoms) is:
\[ 16.00 \, \text{g/mol} \times 2 = 32.00 \, \text{g/mol} \]

2. **Convert grams of O₂ to moles:**
- Use the formula:
\[ \text{moles of O₂} = \frac{\text{mass of O₂ (g)}}{\text{molar mass of O₂ (g/mol)}} \]
- Substitute the values:
\[ \text{moles of O₂} = \frac{4.80 \, \text{g}}{32.00 \, \text{g/mol}} = 0.15 \, \text{mol} \]

3. **Determine the stoichiometry from the balanced equation:**
- According to the balanced equation, 1 mole of O₂ reacts with 2 moles of CO.
- Therefore, if we have 0.15 moles of O₂, the moles of CO needed will be:
\[ \text{moles of CO} = 2 \times \text{moles of O₂} = 2 \times 0.15 \, \text{mol} = 0.30 \, \text{mol} \]

Thus, **0.3 mol** of carbon monoxide (CO) are needed to react with 4.80 g of oxygen gas (O₂) to produce carbon dioxide (CO₂).

The correct response is:
**0.3 mol**