Question

Given the chemical equation 2Fe + 3Cl2 --> 2FeCl3 , how many moles of chlorine gas will be required to react with sufficient iron to produce 14 moles of iron (III) chloride?
Responses

6 mol
6 mol

12 mol
12 mol

9 mol
9 mol

21 mol

Answer 1

To determine how many moles of chlorine gas (Cl₂) are required to react with sufficient iron (Fe) to produce 14 moles of iron (III) chloride (FeCl₃), we can use the stoichiometry from the balanced chemical equation:

\[
2 \text{Fe} + 3 \text{Cl}_2 \rightarrow 2 \text{FeCl}_3
\]

From the equation, we can see the following mole ratio:
- 2 moles of Fe react with 3 moles of Cl₂ to produce 2 moles of FeCl₃.

This means that for every 2 moles of FeCl₃ produced, 3 moles of Cl₂ are required.

If we want to produce 14 moles of FeCl₃, we can set up the following proportion:

\[
\frac{3 \text{ moles of Cl}_2}{2 \text{ moles of FeCl}_3} = \frac{x \text{ moles of Cl}_2}{14 \text{ moles of FeCl}_3}
\]

To find \( x \):

\[
x = \frac{3 \text{ moles of Cl}_2}{2 \text{ moles of FeCl}_3} \times 14 \text{ moles of FeCl}_3 = \frac{3 \times 14}{2} = \frac{42}{2} = 21 \text{ moles of Cl}_2
\]

Thus, **21 moles of chlorine gas (Cl₂)** will be required to produce 14 moles of iron (III) chloride (FeCl₃).

The correct response is:
**21 mol**