Question

Use the chemical equation to answer the question.2H2(g) + O2(g) → 2H2O(l)Which statement describes the breaking and forming of bonds in the reaction?(1 point)ResponsesThe reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds.The reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds.The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds.The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds.The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds.The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds.The reaction requires breaking one O=O bond and two H-H bonds, and then forming four O–H bonds.

Answer 1

To analyze the reaction \(2H_2(g) + O_2(g) \rightarrow 2H_2O(l)\), let's break it down into the bonds involved:

1. **Reactants:**
- Each molecule of \(H_2\) has one H-H bond. Since there are 2 \(H_2\) molecules, this means you have 2 H-H bonds to break in total.
- The \(O_2\) molecule has a double bond (O=O). This means you have 1 O=O bond to break.

2. **Products:**
- Each \(H_2O\) molecule contains two O-H bonds. Since there are 2 \(H_2O\) molecules produced, that means you have 4 O-H bonds formed in total.

So, summarizing the bond breaking and forming:
- **Bonds broken:** 2 H-H bonds and 1 O=O bond.
- **Bonds formed:** 4 O-H bonds.

Now, looking at the provided statements, the correct statement regarding the breaking and forming of bonds in this reaction is:

**"The reaction requires breaking two H–H bonds and one O=O bond, and then forming four O–H bonds."**

This specific phrasing isn’t listed directly in the responses you provided, but it characterizes the reaction correctly based on standard bond-breaking and bond-forming principles. If you can refine the options you provided or double-check the response list, it would help find the closest match based on the information provided.