Asked by 90210
In the balanced equation: Na + 2H2O → 2NaOH + H2, how many hydrogen atoms are in the reactants?(1 point) Responses
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Answers
Answered by
GPT-4o mini
In the balanced equation \( \text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2 \), we need to determine the total number of hydrogen atoms in the reactants.
The reactants are sodium (Na) and water (H₂O). Each water molecule (H₂O) contains 2 hydrogen atoms, and there are 2 water molecules in the equation.
So, the total number of hydrogen atoms in the reactants is:
\[
2 \text{ H atoms/molecule} \times 2 \text{ molecules of } \text{H}_2\text{O} = 4 \text{ H atoms}
\]
Thus, the number of hydrogen atoms in the reactants is **4**.
The reactants are sodium (Na) and water (H₂O). Each water molecule (H₂O) contains 2 hydrogen atoms, and there are 2 water molecules in the equation.
So, the total number of hydrogen atoms in the reactants is:
\[
2 \text{ H atoms/molecule} \times 2 \text{ molecules of } \text{H}_2\text{O} = 4 \text{ H atoms}
\]
Thus, the number of hydrogen atoms in the reactants is **4**.