To determine the balanced equation for the reaction \( \text{V}_2\text{O}_5 + \text{CaS} \rightarrow \text{CaO} + \text{V}_2\text{S}_5 \), we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's break it down:
-
On the left side:
- V: 2 (from \( \text{V}_2\text{O}_5 \))
- O: 5 (from \( \text{V}_2\text{O}_5 \))
- Ca: 1 (from \( \text{CaS} \))
- S: 1 (from \( \text{CaS} \))
-
On the right side:
- V: 2 (from \( \text{V}_2\text{S}_5 \))
- O: 1 (from \( \text{CaO} \))
- Ca: 1 (from \( \text{CaO} \))
- S: 5 (from \( \text{V}_2\text{S}_5 \))
To balance it, we start with the vanadium (V) and sulfur (S) species. The products show that 5 sulfur atoms are produced, so we need to have enough \( \text{CaS} \) to provide this sulfur.
If we try the last option provided:
\( \text{V}_2\text{O}_5 + 5 \text{CaS} \rightarrow 5 \text{CaO} + \text{V}_2\text{S}_5 \)
Check this:
Left Side:
- V: 2
- O: 5
- Ca: 5
- S: 5
Right Side:
- V: 2
- O: 5
- Ca: 5
- S: 5
Both sides are balanced.
Thus, the correct balanced equation is:
\[ \text{V}_2\text{O}_5 + 5 \text{CaS} \rightarrow 5 \text{CaO} + \text{V}_2\text{S}_5 \]
So the answer is:
V2O5 + 5CaS → 5CaO + V2S5.
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