3990 J of heat are added to a 29.9 g sample

Question

of iron at 28◦C. What is the final temperature of the iron? The specific heat of iron is
0.449 J/g · K.
Answer in units of K.

Answer 1

q = mass Fe x specific heat Fe x (Tfinal-Tinitial)
3990 = 29.9 x 0.449 J/g*c x (Tf - 28)
Solve for Tfinal
Post your work if you get stuck.

Answer 2

Yeah I'm stuck-
3990=29.9x0.449x(Tf-28)
3990=13.4251x(Tf-28)
-13.4251=-13.4252
3976.5749=Tf-28
+28=Tf +28
4004.5749=Tf