1)Convert 25* Celsius to Kelvin.
Celsius + 273.15 = Kelvin
Plug the given numbers in this formula and solve for final temperature.
q = mcΔT
where
q = heat energy
m = mass
c = specific heat
ΔT = change in temperature = final temperature - initial temperature
3960 J of heat are added to a 27.6 g sample
of iron at 25
◦
C. What is the final temperature of the iron? The specific heat of iron is
0.449 J/g · K.
Answer in units of K
2 answers
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