Asked by Lindsay
A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 12.6 m higher than A, with speed v/2. Calculate the maximum height reached by the stone above point B.
I am still stuck on this problem, mainly because I can't seem to get v/2. I think I know all the steps...but not having v/2 is keeping me from doing them.
I am still stuck on this problem, mainly because I can't seem to get v/2. I think I know all the steps...but not having v/2 is keeping me from doing them.
Answers
Answered by
bobpursley
well, you know the amount of kinetic energy lost from a to b, and the change in Potential energy
1/2 mv^-1/2 m (v/2)^2= mg12.5
3/4 v^2=12.5*9.8
solve for v.
1/2 mv^-1/2 m (v/2)^2= mg12.5
3/4 v^2=12.5*9.8
solve for v.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.