Question
Use the table to answer the question.
X f(x)
0 32,000
1 29,440
2 27,048.80
3 ?
Sydney bought a new car for $32,000.00. If the car depreciates in value by 8% each year, the situation can be modeled by the equation f(x)=32,000(0.92)x
. Complete the table to find the value of the car to the nearest cent after three years.
(2 points)
The value of the car after three years is $
.
X f(x)
0 32,000
1 29,440
2 27,048.80
3 ?
Sydney bought a new car for $32,000.00. If the car depreciates in value by 8% each year, the situation can be modeled by the equation f(x)=32,000(0.92)x
. Complete the table to find the value of the car to the nearest cent after three years.
(2 points)
The value of the car after three years is $
.
Answers
Answered by
GPT-4o mini
To find the value of the car after three years, we can use the formula provided:
\[
f(x) = 32,000(0.92)^x
\]
We need to calculate \( f(3) \):
\[
f(3) = 32,000(0.92)^3
\]
First, calculate \( 0.92^3 \):
\[
0.92^3 = 0.778688
\]
Now, substitute this value back into the equation:
\[
f(3) = 32,000 \times 0.778688
\]
Calculating this:
\[
f(3) = 32,000 \times 0.778688 \approx 24,973.96
\]
So, the value of the car after three years is approximately:
\[
\text{The value of the car after three years is } \$24,973.96.
\]
Final answer:
**$24,973.96**
\[
f(x) = 32,000(0.92)^x
\]
We need to calculate \( f(3) \):
\[
f(3) = 32,000(0.92)^3
\]
First, calculate \( 0.92^3 \):
\[
0.92^3 = 0.778688
\]
Now, substitute this value back into the equation:
\[
f(3) = 32,000 \times 0.778688
\]
Calculating this:
\[
f(3) = 32,000 \times 0.778688 \approx 24,973.96
\]
So, the value of the car after three years is approximately:
\[
\text{The value of the car after three years is } \$24,973.96.
\]
Final answer:
**$24,973.96**
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