The equation is H2SO4 + 2NaOH ==>Na2SO4 + 2H2O
moles NaOH = M x L = 1 x 0.020 = 0.02.
moles H2SO4 = 0.02 x (1 mole H2SO4/2 moles NaOH) = 0.01 mole H2SO4
M H2SO4 = mols/L = 0.01 moles/0.01 L (that's 10 mL) = 1 M H2SO4. I don't know how to make it 11 M.
IF 10ml of H2SO4 is need to neutralize 20ml of 1N NaOH, how many milliliters of H2SO4 is needed to make 1 liter of 11M solution?
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