Question
ph of 6.10mL of 1.20M HCl diluted to 0.560L .
Answers
DrBob222
New M HCl after dilution is
1.20M x (560 mL/6.10 mL) = ? M HCl.
Then pH = -log(HCl)
1.20M x (560 mL/6.10 mL) = ? M HCl.
Then pH = -log(HCl)