Question
Tell whether each expression in the table is equivalent to 5^2, 5^-2, or neither.
A.) (5^-1)^2
B.) (5^-1)^-1
C.) (1/5)^2
D.) (1/5)^-2
A.) (5^-1)^2
B.) (5^-1)^-1
C.) (1/5)^2
D.) (1/5)^-2
Answers
Answered by
GPT-4o mini
To determine whether each expression is equivalent to \(5^2\), \(5^{-2}\), or neither, we will simplify each expression:
A.) \((5^{-1})^2\)
\[
(5^{-1})^2 = 5^{-2}
\]
This is equivalent to \(5^{-2}\).
B.) \((5^{-1})^{-1}\)
\[
(5^{-1})^{-1} = 5^{(-1)(-1)} = 5^1
\]
This is neither \(5^2\) nor \(5^{-2}\).
C.) \((1/5)^2\)
\[
(1/5)^2 = \frac{1^2}{5^2} = \frac{1}{5^2} = 5^{-2}
\]
This is equivalent to \(5^{-2}\).
D.) \((1/5)^{-2}\)
\[
(1/5)^{-2} = (5^{-1})^{-2} = 5^{(-1)(-2)} = 5^2
\]
This is equivalent to \(5^2\).
Now let's summarize:
- A.) \(5^{-2}\)
- B.) Neither
- C.) \(5^{-2}\)
- D.) \(5^2\)
A.) \((5^{-1})^2\)
\[
(5^{-1})^2 = 5^{-2}
\]
This is equivalent to \(5^{-2}\).
B.) \((5^{-1})^{-1}\)
\[
(5^{-1})^{-1} = 5^{(-1)(-1)} = 5^1
\]
This is neither \(5^2\) nor \(5^{-2}\).
C.) \((1/5)^2\)
\[
(1/5)^2 = \frac{1^2}{5^2} = \frac{1}{5^2} = 5^{-2}
\]
This is equivalent to \(5^{-2}\).
D.) \((1/5)^{-2}\)
\[
(1/5)^{-2} = (5^{-1})^{-2} = 5^{(-1)(-2)} = 5^2
\]
This is equivalent to \(5^2\).
Now let's summarize:
- A.) \(5^{-2}\)
- B.) Neither
- C.) \(5^{-2}\)
- D.) \(5^2\)
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