Question

In the absence of air resistance two balls are thrown upward from the same launch point. Ball A rises to a maximum height above the launch point that is four times greater than that of ball B. The launch speed of ball A is _______ times greater than that of ball B.

a)2 b)4 c)8 d)16

I realize that the velocity of either ball at the top of its flight is v= 0 m/s, but do not know which kinematic equation relates maximum height and launch speed. Any help on this would be great thanks!

Answer 1

The maximum height achieved is proportional to the initial kinetic energy, which is proportional to V^2.

What do you have to do to V in order to increase V^2 by a factor of 4?

Answer 2

I still do not understand what do you mean by initial kinetic energy? what equations are proportionate to each other I do not understand what you are trying to say

Answer 3

b)4