Question
If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by
1/R= 1/R1+ 1/R2.
If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 110 Ω?
1/R= 1/R1+ 1/R2.
If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 110 Ω?
Answers
MANOJ
0.1360 OHMS PER SECONDS
Anonymous
0.154ohms/s