Question

Consider this sequence of bits:
\[\texttt{110}\texttt{0}\texttt{0}\texttt{0}\texttt{1111110}\texttt{0111111101110}\texttt{0}\texttt{0}\texttt{0}\texttt{0}\texttt{0}\texttt{1}\]
How many bytes long is that sequence of bits?
Choose 1 answer:
Choose 1 answer:
(Choice A) \[32\]
A
\[32\]
(Choice B) \[4\]
B
\[4\]
(Choice C) \[2\]
C
\[2\]
(Choice D) \[8\]
D
\[8\]

Answer 1

To determine the number of bytes in the sequence of bits, we first need to count the total number of bits in the sequence.

The sequence given is:
\[
\texttt{110}\texttt{0}\texttt{0}\texttt{0}\texttt{1111110}\texttt{0111111101110}\texttt{0}\texttt{0}\texttt{0}\texttt{0}\texttt{0}\texttt{1}
\]

Let's break this down and count the bits:

1. \texttt{110} has 3 bits.
2. \texttt{0}\texttt{0}\texttt{0} has 3 bits (3 zeros).
3. \texttt{1111110} has 7 bits.
4. \texttt{0111111101110} has 13 bits.
5. \texttt{0}\texttt{0}\texttt{0}\texttt{0}\texttt{0} has 5 bits (5 zeros).
6. \texttt{1} has 1 bit.

Now, we calculate the total number of bits:

- From step 1: 3 bits
- From step 2: 3 bits
- From step 3: 7 bits
- From step 4: 13 bits
- From step 5: 5 bits
- From step 6: 1 bit

Adding these together:
\[
3 + 3 + 7 + 13 + 5 + 1 = 32 \text{ bits}
\]

Since there are 8 bits in a byte, we can convert the total number of bits to bytes:
\[
\frac{32 \text{ bits}}{8 \text{ bits/byte}} = 4 \text{ bytes}
\]

Thus, the sequence is 4 bytes long.

The answer is:
(Choice B) \[4\]