Question

Consider this sequence of bits:
\[\texttt{1011111111010}\texttt{0}\texttt{0}\texttt{111111101}\]
How many bytes long is that sequence of bits?
Choose 1 answer:
Choose 1 answer:
(Choice A) \[3\]
A
\[3\]
(Choice B) \[12\]
B
\[12\]
(Choice C) \[4\]
C
\[4\]
(Choice D) \[24\]
D
\[24\]

Answer 1

To determine how many bytes long the given sequence of bits is, we first need to count the total number of bits in the sequence.

The sequence of bits provided is:

\[\texttt{1011111111010}\texttt{0}\texttt{0}\texttt{111111101}\]

Counting the bits in the sequence:

- The first part is \(\texttt{1011111111010}\) which has 13 bits.
- The next part, which consists of two zeros, contributes 2 bits.
- The last part, \(\texttt{111111101}\), has 9 bits.

Now, we can calculate the total number of bits:

\[
13 + 2 + 9 = 24\ \text{bits}
\]

Next, we need to convert the total number of bits into bytes. Since 1 byte is equal to 8 bits, we can find the number of bytes by dividing the total bits by 8:

\[
\text{Number of bytes} = \frac{24\ \text{bits}}{8\ \text{bits/byte}} = 3\ \text{bytes}
\]

Therefore, the sequence of bits is \(3\) bytes long.

The correct answer is:

(Choice A) \[3\]