A ball is dropped from a cliff and has an acceleration of 9.8 m/s2. How long will it take the ball to reach a speed of 24.5 m/s?

1 answer

We can use the formula for acceleration:

a = (v - u) / t

where a is acceleration, v is the final velocity, u is the initial velocity, and t is time. Since the ball is dropped, u = 0. We want to find t, so we can rearrange the formula:

t = (v - u) / a

Plugging in the values:

t = (24.5 m/s - 0 m/s) / 9.8 m/s^2

t = 24.5 m/s / 9.8 m/s^2

t ≈ 2.5 seconds

The ball will take approximately 2.5 seconds to reach a speed of 24.5 m/s.