Asked by Rob
A ball is dropped from a cliff and 2 seconds later, a second ball is thrown vertically downward. What must be the initial velocity of the second ball if it overtakes the first ball as it passes 400m ?
Answers
Answered by
Steve
If you mean that the balls pass as they have both fallen 400m, then you have
4.9t^2 = 400
v(t-2)+4.9(t-2)^2 = 400
v(20/√4.9-2)+4.9(20/√4.9-2)^2 = 400
v = 22.39 m/s
4.9t^2 = 400
v(t-2)+4.9(t-2)^2 = 400
v(20/√4.9-2)+4.9(20/√4.9-2)^2 = 400
v = 22.39 m/s
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