Question
What is the approximate volume of the sugar container?
radius=2.5in
height=8in
volume =?in3
radius=2.5in
height=8in
volume =?in3
Answers
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
\text{Volume} = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.
Given:
- Radius \( r = 2.5 \) inches
- Height \( h = 8 \) inches
Now plug in the values into the formula:
\[
\text{Volume} = \pi (2.5)^2 (8)
\]
Calculating \( (2.5)^2 \):
\[
(2.5)^2 = 6.25
\]
Then plug this value back into the volume formula:
\[
\text{Volume} = \pi (6.25)(8)
\]
Calculating \( 6.25 \times 8 \):
\[
6.25 \times 8 = 50
\]
So now we have:
\[
\text{Volume} = 50\pi
\]
Approximating \( \pi \) as \( 3.14 \):
\[
\text{Volume} \approx 50 \times 3.14 = 157
\]
Thus, the approximate volume of the sugar container is:
\[
\boxed{157 \, \text{in}^3}
\]
\[
\text{Volume} = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.
Given:
- Radius \( r = 2.5 \) inches
- Height \( h = 8 \) inches
Now plug in the values into the formula:
\[
\text{Volume} = \pi (2.5)^2 (8)
\]
Calculating \( (2.5)^2 \):
\[
(2.5)^2 = 6.25
\]
Then plug this value back into the volume formula:
\[
\text{Volume} = \pi (6.25)(8)
\]
Calculating \( 6.25 \times 8 \):
\[
6.25 \times 8 = 50
\]
So now we have:
\[
\text{Volume} = 50\pi
\]
Approximating \( \pi \) as \( 3.14 \):
\[
\text{Volume} \approx 50 \times 3.14 = 157
\]
Thus, the approximate volume of the sugar container is:
\[
\boxed{157 \, \text{in}^3}
\]