Question
What is the approximate volume of the cylinder of 4cm and 9cm? Use 3.14 for π.
Answers
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
Given that the diameter of the cylinder is 4 cm, the radius \( r \) will be half of the diameter:
\[
r = \frac{4 \text{ cm}}{2} = 2 \text{ cm}
\]
The height \( h \) of the cylinder is given as 9 cm.
Now, substitute the values into the volume formula:
\[
V = 3.14 \times (2 \text{ cm})^2 \times 9 \text{ cm}
\]
Calculate \( (2 \text{ cm})^2 \):
\[
(2 \text{ cm})^2 = 4 \text{ cm}^2
\]
Now substitute that into the formula:
\[
V = 3.14 \times 4 \text{ cm}^2 \times 9 \text{ cm}
\]
Calculate \( 4 \times 9 \):
\[
4 \times 9 = 36
\]
Now, substitute back:
\[
V = 3.14 \times 36 \text{ cm}^3
\]
Now, calculate \( 3.14 \times 36 \):
\[
V \approx 113.04 \text{ cm}^3
\]
Therefore, the approximate volume of the cylinder is \( 113.04 \text{ cm}^3 \).
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
Given that the diameter of the cylinder is 4 cm, the radius \( r \) will be half of the diameter:
\[
r = \frac{4 \text{ cm}}{2} = 2 \text{ cm}
\]
The height \( h \) of the cylinder is given as 9 cm.
Now, substitute the values into the volume formula:
\[
V = 3.14 \times (2 \text{ cm})^2 \times 9 \text{ cm}
\]
Calculate \( (2 \text{ cm})^2 \):
\[
(2 \text{ cm})^2 = 4 \text{ cm}^2
\]
Now substitute that into the formula:
\[
V = 3.14 \times 4 \text{ cm}^2 \times 9 \text{ cm}
\]
Calculate \( 4 \times 9 \):
\[
4 \times 9 = 36
\]
Now, substitute back:
\[
V = 3.14 \times 36 \text{ cm}^3
\]
Now, calculate \( 3.14 \times 36 \):
\[
V \approx 113.04 \text{ cm}^3
\]
Therefore, the approximate volume of the cylinder is \( 113.04 \text{ cm}^3 \).