Question
Draw ten cards from a deck of 52 standard. Find the probability of getting at least one ace.
Answers
drwls
1 minus the probability of getting NO aces in ten draws. Assuming no cards are replaced after drawing,
1 - (48/52)(47/51)(46/50)(45/49)(44/48)(43/47)(42/46)(41/45)(40/44)(39/43)
= 1 - 42*41*40*39/(52*51*50*49)
= 1 - 0.413445 = 0.586555
1 - (48/52)(47/51)(46/50)(45/49)(44/48)(43/47)(42/46)(41/45)(40/44)(39/43)
= 1 - 42*41*40*39/(52*51*50*49)
= 1 - 0.413445 = 0.586555