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From a deck of 52 cards, how many different four-card hands could be dealt which include one card from each suit?
14 years ago

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Reiny
We need one form the hearts, one from the clubs etc.

number = C(13,1)x C(13,1) x C(13,1) x C(13,1)
= 13^4 = ....
14 years ago
kitkat
ok thanks I just wanted to make sure I did it right
14 years ago

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