Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Determine the approximate solution to the equation 2⋅3^x=10 using a graph.(1 point) Responses x≈1.7 x approximately equals 1.7...Asked by bloozoo
Determine the approximate solution to the equation 2⋅3x=10
using a graph.(1 point)
Responses
x≈2
x approximately equals 2
x≈10
x approximately equals 10
x≈1.5
x approximately equals 1.5
x≈1.7
using a graph.(1 point)
Responses
x≈2
x approximately equals 2
x≈10
x approximately equals 10
x≈1.5
x approximately equals 1.5
x≈1.7
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation \( 2 \cdot 3^x = 10 \) using a graph, we can rearrange it to find the value of \( x \) where the two sides of the equation are equal. We can express it as:
\[ y = 2 \cdot 3^x \]
and
\[ y = 10 \]
Now, we need to find the intersection of these two functions to determine \( x \).
When we graph the function \( y = 2 \cdot 3^x \), we can evaluate its values for different \( x \):
- For \( x = 0 \):
\[ y = 2 \cdot 3^0 = 2 \cdot 1 = 2 \]
- For \( x = 1 \):
\[ y = 2 \cdot 3^1 = 2 \cdot 3 = 6 \]
- For \( x = 2 \):
\[ y = 2 \cdot 3^2 = 2 \cdot 9 = 18 \]
We can see that the function \( y = 2 \cdot 3^x \) grows rapidly.
Now, looking for where this function equals 10, we see:
1. At \( x = 1 \), \( y = 6 \) (too low)
2. At \( x = 2 \), \( y = 18 \) (too high)
3. So the solution must be between \( x = 1 \) and \( x = 2 \).
To find a more precise estimate:
- For \( x \approx 1.5 \):
\[ y = 2 \cdot 3^{1.5} = 2 \cdot \sqrt{27} \approx 10.39 \] (too high)
- For \( x \approx 1.3 \):
\[ y = 2 \cdot 3^{1.3} \approx 7.72 \] (too low)
- For \( x \approx 1.4 \):
\[ y = 2 \cdot 3^{1.4} \approx 9.06 \] (still too low)
- For \( x \approx 1.45 \):
\[ y \approx 9.74 \] (still too low)
- For \( x \approx 1.47 \):
\[ y \approx 10.03 \] (just above)
- For \( x \approx 1.46 \):
\[ y \approx 9.93 \] (just below)
Thus, the approximate solution is closer to \( 1.47 \), but if we consider the options given:
- \( x \approx 1.5 \) is the closest estimate.
**Therefore, the approximate solution is:**
**x ≈ 1.5**
\[ y = 2 \cdot 3^x \]
and
\[ y = 10 \]
Now, we need to find the intersection of these two functions to determine \( x \).
When we graph the function \( y = 2 \cdot 3^x \), we can evaluate its values for different \( x \):
- For \( x = 0 \):
\[ y = 2 \cdot 3^0 = 2 \cdot 1 = 2 \]
- For \( x = 1 \):
\[ y = 2 \cdot 3^1 = 2 \cdot 3 = 6 \]
- For \( x = 2 \):
\[ y = 2 \cdot 3^2 = 2 \cdot 9 = 18 \]
We can see that the function \( y = 2 \cdot 3^x \) grows rapidly.
Now, looking for where this function equals 10, we see:
1. At \( x = 1 \), \( y = 6 \) (too low)
2. At \( x = 2 \), \( y = 18 \) (too high)
3. So the solution must be between \( x = 1 \) and \( x = 2 \).
To find a more precise estimate:
- For \( x \approx 1.5 \):
\[ y = 2 \cdot 3^{1.5} = 2 \cdot \sqrt{27} \approx 10.39 \] (too high)
- For \( x \approx 1.3 \):
\[ y = 2 \cdot 3^{1.3} \approx 7.72 \] (too low)
- For \( x \approx 1.4 \):
\[ y = 2 \cdot 3^{1.4} \approx 9.06 \] (still too low)
- For \( x \approx 1.45 \):
\[ y \approx 9.74 \] (still too low)
- For \( x \approx 1.47 \):
\[ y \approx 10.03 \] (just above)
- For \( x \approx 1.46 \):
\[ y \approx 9.93 \] (just below)
Thus, the approximate solution is closer to \( 1.47 \), but if we consider the options given:
- \( x \approx 1.5 \) is the closest estimate.
**Therefore, the approximate solution is:**
**x ≈ 1.5**
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.