Asked by Eddie
Determine the [OH^-] of a solution that is 0.145 M in CO3^2-.
Answers
Answered by
DrBob222
Write the hydrolysis of CO3^-2.
CO3^-2 + HOH ==> HCO3^- + OH^-
Now set up an ICE chart and solve for the Kb expression which is
Kb = (Kw/k2) = (HCO3^-)(OH^-)/(CO3^-2)
CO3^-2 + HOH ==> HCO3^- + OH^-
Now set up an ICE chart and solve for the Kb expression which is
Kb = (Kw/k2) = (HCO3^-)(OH^-)/(CO3^-2)
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