2x^2 - 3x + 6 = 0.
x = 3+- sqrt(9 - 48) / 4 =
3 +- sqrt(-39) / 4 =
(3 +- sqrt(39*-1)) / 4
sqrt(-1) = i
x = +- isqrt(39) / 4
Solution Set:
x =(3 - isqrt(39)) / 4
x =(3 + isqrt(39)) / 4
use the quadratic formula to solve the equation 2x^2-3x=-6
1 answer