In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point) Responses a car that traveled 80 kilometers on 5.0 liters of gas a car that traveled 80 kilometers on 5.0 liters of gas a car that traveled 50 kilometers on 4.0 liters of gas a car that traveled 50 kilometers on 4.0 liters of gas a car that traveled 90 kilometers on 6.0 liters of gas a car that traveled 90 kilometers on 6.0 liters of gas a car that traveled 70 kilometers on 5.0 liters of gas a car that traveled 70 kilometers on 5.0 liters of gas

1 answer

To determine which car achieved the greatest efficiency, we need to calculate the fuel efficiency (kilometers per liter) for each of the given situations. The formula for fuel efficiency is:

\[ \text{Fuel Efficiency} = \frac{\text{Distance (km)}}{\text{Fuel Used (liters)}} \]

Now let's calculate the fuel efficiency for each car:

  1. Car that traveled 80 kilometers on 5.0 liters of gas: \[ \text{Efficiency} = \frac{80 \text{ km}}{5.0 \text{ liters}} = 16 \text{ km/l} \]

  2. Car that traveled 50 kilometers on 4.0 liters of gas: \[ \text{Efficiency} = \frac{50 \text{ km}}{4.0 \text{ liters}} = 12.5 \text{ km/l} \]

  3. Car that traveled 90 kilometers on 6.0 liters of gas: \[ \text{Efficiency} = \frac{90 \text{ km}}{6.0 \text{ liters}} = 15 \text{ km/l} \]

  4. Car that traveled 70 kilometers on 5.0 liters of gas: \[ \text{Efficiency} = \frac{70 \text{ km}}{5.0 \text{ liters}} = 14 \text{ km/l} \]

Now, let's compare the fuel efficiencies:

  • Car 1: 16 km/l
  • Car 2: 12.5 km/l
  • Car 3: 15 km/l
  • Car 4: 14 km/l

The car that traveled 80 kilometers on 5.0 liters of gas achieved the greatest efficiency of 16 km/l.