Question

In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point) Responses a car that traveled 80 kilometers on 5.0 liters of gas a car that traveled 80 kilometers on 5.0 liters of gas a car that traveled 50 kilometers on 4.0 liters of gas a car that traveled 50 kilometers on 4.0 liters of gas a car that traveled 90 kilometers on 6.0 liters of gas a car that traveled 90 kilometers on 6.0 liters of gas a car that traveled 70 kilometers on 5.0 liters of gas a car that traveled 70 kilometers on 5.0 liters of gas

Answer 1

To determine which car achieved the greatest efficiency, we need to calculate the fuel efficiency (kilometers per liter) for each of the given situations. The formula for fuel efficiency is:

\[
\text{Fuel Efficiency} = \frac{\text{Distance (km)}}{\text{Fuel Used (liters)}}
\]

Now let's calculate the fuel efficiency for each car:

1. **Car that traveled 80 kilometers on 5.0 liters of gas:**
\[
\text{Efficiency} = \frac{80 \text{ km}}{5.0 \text{ liters}} = 16 \text{ km/l}
\]

2. **Car that traveled 50 kilometers on 4.0 liters of gas:**
\[
\text{Efficiency} = \frac{50 \text{ km}}{4.0 \text{ liters}} = 12.5 \text{ km/l}
\]

3. **Car that traveled 90 kilometers on 6.0 liters of gas:**
\[
\text{Efficiency} = \frac{90 \text{ km}}{6.0 \text{ liters}} = 15 \text{ km/l}
\]

4. **Car that traveled 70 kilometers on 5.0 liters of gas:**
\[
\text{Efficiency} = \frac{70 \text{ km}}{5.0 \text{ liters}} = 14 \text{ km/l}
\]

Now, let's compare the fuel efficiencies:
- Car 1: 16 km/l
- Car 2: 12.5 km/l
- Car 3: 15 km/l
- Car 4: 14 km/l

The car that traveled **80 kilometers on 5.0 liters of gas** achieved the greatest efficiency of **16 km/l**.