Question

In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point)
Responses

a car that traveled 50 kilometers on 4.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas

a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas

a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas

a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 70 kilometers on 5.0 liters of gas

Answer 1

To determine which car achieved the greatest efficiency in terms of kilometers per liter of gas, we can calculate the fuel efficiency for each situation. The formula for fuel efficiency (in kilometers per liter) is:

\[
\text{Efficiency} = \frac{\text{Distance (km)}}{\text{Fuel (liters)}}
\]

Now let's calculate the efficiency for each option:

1. **First option:** 50 kilometers on 4.0 liters
\[
\text{Efficiency} = \frac{50}{4.0} = 12.5 \text{ km/l}
\]

2. **Second option:** 90 kilometers on 6.0 liters
\[
\text{Efficiency} = \frac{90}{6.0} = 15.0 \text{ km/l}
\]

3. **Third option:** 80 kilometers on 5.0 liters
\[
\text{Efficiency} = \frac{80}{5.0} = 16.0 \text{ km/l}
\]

4. **Fourth option:** 70 kilometers on 5.0 liters
\[
\text{Efficiency} = \frac{70}{5.0} = 14.0 \text{ km/l}
\]

Now we can compare the efficiencies calculated:

- First option: 12.5 km/l
- Second option: 15.0 km/l
- Third option: 16.0 km/l
- Fourth option: 14.0 km/l

The car that traveled 80 kilometers on 5.0 liters of gas achieved the greatest efficiency at **16.0 km/l.**