Question
page 14 of 14 Area of a Model Quick Check 1 of 51 of 5 Items Question Constantinos is painting a rectangular outline of a frame on the wall, leaving the area inside unpainted. He wants the outside of the frame to be 9 ft. wide by 12 ft. tall. The inside of the frame will be 6 ft. wide by 10 ft. tall. Calculate the area of the frame.(1 point) Responses 60 ft.2 60 ft. squared 108 ft.2 108 ft. squared 48 ft.2 48 ft. squared 168 ft.2 168 ft. squared Skip to navigation
Answers
GPT-4o mini
To find the area of the frame that Constantinos is painting, we first need to calculate the area of the outer rectangle (the outside of the frame) and the area of the inner rectangle (the unpainted area inside the frame).
1. **Calculate the area of the outer rectangle**:
- Width = 9 ft
- Height = 12 ft
- Area (outer) = Width × Height = 9 ft × 12 ft = 108 ft²
2. **Calculate the area of the inner rectangle**:
- Width = 6 ft
- Height = 10 ft
- Area (inner) = Width × Height = 6 ft × 10 ft = 60 ft²
3. **Calculate the area of the frame**:
- Area (frame) = Area (outer) - Area (inner) = 108 ft² - 60 ft² = 48 ft²
Therefore, the area of the frame is **48 ft²**.
The correct answer is **48 ft.²** or **48 ft squared**.
1. **Calculate the area of the outer rectangle**:
- Width = 9 ft
- Height = 12 ft
- Area (outer) = Width × Height = 9 ft × 12 ft = 108 ft²
2. **Calculate the area of the inner rectangle**:
- Width = 6 ft
- Height = 10 ft
- Area (inner) = Width × Height = 6 ft × 10 ft = 60 ft²
3. **Calculate the area of the frame**:
- Area (frame) = Area (outer) - Area (inner) = 108 ft² - 60 ft² = 48 ft²
Therefore, the area of the frame is **48 ft²**.
The correct answer is **48 ft.²** or **48 ft squared**.