Asked by Z32
(Vectors) If |A x B| = 6.45AB, what is the angle between A and B?
Answers
Answered by
drwls
If you mean
|A x B| = 6.45A*B,
where A*B is the dot product, then
|A||B|sin theta = 6.45 |A||B|cos theta
tan theta = 6.45, and
theta = 81.2 degrees
|A x B| = 6.45A*B,
where A*B is the dot product, then
|A||B|sin theta = 6.45 |A||B|cos theta
tan theta = 6.45, and
theta = 81.2 degrees
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