Question

add 12x to both sides of the equation to get rid of the −12x on the right, and get all the x terms on the left side of the equation.
y= 2x−1
x= −6y+20
x
=
−6(2x−1) + 20

x
=
−6(2x+−1) + 20

x
=
−12x + 6 + 20

x
=
−12x + 26
+
12x
+
12x

=

Answer 1

Let's start with the equations you provided and simplify them step by step:

1. You have \( y = 2x - 1 \).
2. Substitute \( y \) in the equation \( x = -6y + 20 \) to get:
\[
x = -6(2x - 1) + 20
\]

3. Distribute \(-6\):
\[
x = -12x + 6 + 20
\]

4. Combine like terms:
\[
x = -12x + 26
\]

5. Now, add \( 12x \) to both sides to isolate \( x \):
\[
x + 12x = 26
\]
\[
13x = 26
\]

6. Finally, solve for \( x \):
\[
x = \frac{26}{13} = 2
\]

So, the final value of \( x \) is \( 2 \).