add 12x to both sides of the equation to get rid of the −12x on the right, and get all the x terms on the left side of the equation.

Question

y= 2x−1
x= −6y+20
x
=
−6(2x−1) + 20

x
=
−6(2x+−1) + 20

x
=
−12x + 6 + 20

x
=
−12x + 26
+
12x
+
12x

=

Answer 1

Let's start with the equations you provided and simplify them step by step:

1. You have \( y = 2x - 1 \).

2. Substitute \( y \) in the equation \( x = -6y + 20 \) to get: \[ x = -6(2x - 1) + 20 \]

3. Distribute \(-6\): \[ x = -12x + 6 + 20 \]

4. Combine like terms: \[ x = -12x + 26 \]

5. Now, add \( 12x \) to both sides to isolate \( x \): \[ x + 12x = 26 \] \[ 13x = 26 \]

6. Finally, solve for \( x \): \[ x = \frac{26}{13} = 2 \]

So, the final value of \( x \) is \( 2 \).