Question
subtract p from both sides of the equation to rewrite this equation in terms of s.
0.75s+0.5p = 13
s+p = 20
s+p
=
20
−
p
−
p
=
0.75s+0.5p = 13
s+p = 20
s+p
=
20
−
p
−
p
=
Answers
Answered by
GPT-4o mini
To rewrite the given equations in terms of \( s \), we start with the second equation:
\[ s + p = 20 \]
We can isolate \( s \) by subtracting \( p \) from both sides:
\[ s = 20 - p \]
Now we have expressed \( s \) in terms of \( p \). If you would like to substitute this expression for \( s \) into the first equation, we can do that too. The first equation is:
\[ 0.75s + 0.5p = 13 \]
Substituting \( s = 20 - p \) into this equation:
\[ 0.75(20 - p) + 0.5p = 13 \]
Now, distribute \( 0.75 \):
\[ 15 - 0.75p + 0.5p = 13 \]
Combine like terms:
\[ 15 - 0.25p = 13 \]
Now, isolate \( p \) by subtracting 15 from both sides:
\[ -0.25p = 13 - 15 \]
\[ -0.25p = -2 \]
Now divide by -0.25:
\[ p = \frac{-2}{-0.25} = 8 \]
Then, substitute \( p = 8 \) back into \( s = 20 - p \):
\[ s = 20 - 8 \]
\[ s = 12 \]
Thus, the translated form of your original equations leads us to:
- \( s = 20 - p \)
- When \( p = 8 \), then \( s = 12 \).
\[ s + p = 20 \]
We can isolate \( s \) by subtracting \( p \) from both sides:
\[ s = 20 - p \]
Now we have expressed \( s \) in terms of \( p \). If you would like to substitute this expression for \( s \) into the first equation, we can do that too. The first equation is:
\[ 0.75s + 0.5p = 13 \]
Substituting \( s = 20 - p \) into this equation:
\[ 0.75(20 - p) + 0.5p = 13 \]
Now, distribute \( 0.75 \):
\[ 15 - 0.75p + 0.5p = 13 \]
Combine like terms:
\[ 15 - 0.25p = 13 \]
Now, isolate \( p \) by subtracting 15 from both sides:
\[ -0.25p = 13 - 15 \]
\[ -0.25p = -2 \]
Now divide by -0.25:
\[ p = \frac{-2}{-0.25} = 8 \]
Then, substitute \( p = 8 \) back into \( s = 20 - p \):
\[ s = 20 - 8 \]
\[ s = 12 \]
Thus, the translated form of your original equations leads us to:
- \( s = 20 - p \)
- When \( p = 8 \), then \( s = 12 \).