Subtract h from both sides of the equation to get rid of the h on the left, so that all the h terms are on the right side of the equation.

Question

5
1
​
(5h−15)
=
9h+9

h − 3
=
9h + 9
−
h
−
h

=

Answer 1

To subtract $h$ from both sides of the equation $h-3=9h+9$:

1. Start with the original equation:

   $$h-3=9h+9$$

2. Subtract $h$ from both sides:

   $$h-h-3=9h-h+9$$

   This simplifies to:

   $$-3=8h+9$$

So, after moving $h$ from the left side to the right side, you get:

$$-3=8h+9$$