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The cost in millions to remove x% of pollution in a lake modeled by C=6000/200-2x. What is the cost to remove 75% of the pollut...Asked by Carla
The cost in millions to remove x% of pollution in a lake modeled by
C=6000/200-2x.
What is the cost to remove 75% of the pollutant?
What is the cost to remove 99% of the pollutant?
For what value is this equation undefined?
Answers
Answered by
Kel
C=6000/(200-2X) I'LL ASSUME THIS IS THE EQUATION.
C=6000/(200-2*75)
C=6000/(200-150)
C=6000/50
C=120 COST TO REMOVE 75%.
C=6000/(200-2*90)
C=6000/(200-180)
C=6000/20
C=300 COST TO REMOVE 90%.
C=6000/(200-2*99)
C=6000/(200-198)
C=6000/2
C=3000 COST TO REMOVE 99%.
THE EQUATION IS UNDEFINED WHEN YOU USE 100%.
C=6000/(200-200)
C=6000/0 C BECOMES UNDEFINED WHEN YOU DIVIDE BY 0.
C=6000/(200-2*75)
C=6000/(200-150)
C=6000/50
C=120 COST TO REMOVE 75%.
C=6000/(200-2*90)
C=6000/(200-180)
C=6000/20
C=300 COST TO REMOVE 90%.
C=6000/(200-2*99)
C=6000/(200-198)
C=6000/2
C=3000 COST TO REMOVE 99%.
THE EQUATION IS UNDEFINED WHEN YOU USE 100%.
C=6000/(200-200)
C=6000/0 C BECOMES UNDEFINED WHEN YOU DIVIDE BY 0.
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