To find the volumes of both rectangular prisms, we can use the formula for the volume of a rectangular prism, which is:
\[ \text{Volume} = \text{Base Area} \times \text{Height} \]
For the first rectangular prism:
- Base dimensions: \(22 , \text{m} \times 55 , \text{m}\)
- Height: \(44 , \text{m}\)
Calculating the volume:
\[ \text{Volume}_1 = (22 , \text{m} \times 55 , \text{m}) \times 44 , \text{m} \]
Calculating the base area:
\[ 22 \times 55 = 1210 , \text{m}^2 \]
Then, the volume becomes:
\[ \text{Volume}_1 = 1210 , \text{m}^2 \times 44 , \text{m} = 53240 , \text{m}^3 \]
For the second rectangular prism:
- Base dimensions: \(55 , \text{m} \times 44 , \text{m}\)
- Height: \(22 , \text{m}\)
Calculating the volume:
\[ \text{Volume}_2 = (55 , \text{m} \times 44 , \text{m}) \times 22 , \text{m} \]
Calculating the base area:
\[ 55 \times 44 = 2420 , \text{m}^2 \]
Then, the volume becomes:
\[ \text{Volume}_2 = 2420 , \text{m}^2 \times 22 , \text{m} = 53240 , \text{m}^3 \]
Now we can compare the volumes of both prisms:
\[ \text{Volume}_1 = 53240 , \text{m}^3 \] \[ \text{Volume}_2 = 53240 , \text{m}^3 \]
The volume of the first rectangular prism is equal to the volume of the second rectangular prism.
Thus, regardless of the rearrangement of the dimensions or orientations, both prisms occupy the same volume of \(53240 , \text{m}^3\).