Question

Now, divide both sides of the equation by 9π to get rid of the 9π and get h alone on the right side of the equation.
r= 3Area Label Arrow
height = ?
Volume = 63π
Volume
=
Area of base · height

V
=
πr
2
·h

63π
=
π · 3
2
·h

63π
=
π · 9 · h

63π
=
9π·h
9π
9π

=

Answer 1

To isolate \( h \) in your equation \( 63\pi = 9\pi \cdot h \), you can divide both sides by \( 9\pi \).

Starting with:

\[
63\pi = 9\pi \cdot h
\]

Divide both sides by \( 9\pi \):

\[
\frac{63\pi}{9\pi} = h
\]

The \( \pi \) cancels out on both sides:

\[
\frac{63}{9} = h
\]

Now, simplifying \( \frac{63}{9} \):

\[
h = 7
\]

So, \( h \) alone is:

\[
h = 7
\]