Question

The college athletic director recorded the highest noise levels reached during 9 sporting events. The highs were:
86 decibels86 decibels93 decibels82 decibels84 decibels94 decibels85 decibels91 decibels82 decibels
What was the mean noise level recorded?

Answer 1

To calculate the mean noise level, you need to follow these steps:

1. **Add all the decibel levels together**.
2. **Divide the total by the number of events**.

Here are the noise levels recorded:

- 86 decibels
- 93 decibels
- 82 decibels
- 84 decibels
- 94 decibels
- 85 decibels
- 91 decibels
- 82 decibels

Now let's sum these values:

\[
86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 86 + 93 + 82 + 84 + 94 + 85 + 91 + 82 = 686
\]

The total of the noise levels is **686 decibels**.

2. **Divide by the number of events (8)**:

\[
\text{Mean} = \frac{\text{Total sum}}{\text{Number of events}} = \frac{686}{8} = 85.75
\]

Thus, the mean noise level recorded is **85.75 decibels**.