Question

An athletic director wants to buy soccer balls and footballs.

Each soccer ball costs $15.
Each football costs $20.
The director can spend no more than $150 in all.
The graph shown models this situation, where x is the number of soccer balls and y is the number of footballs.



Which inequality represents this situation?

(1 point)
Responses

20x+15y≥150
20 x plus 15 y is greater than or equal to 150

20x+15y≤150
20 x plus 15 y is less than or equal to 150

15x+20y≥150
15 x plus 20 y is greater than or equal to 150

15x+20y≤150
15 x plus 20 y is less than or equal to 150
Skip to navigation

Answer 1

To set up the inequality based on the given information, we need to consider the costs associated with soccer balls and footballs.

Let:
- \( x \) = number of soccer balls
- \( y \) = number of footballs

The cost of soccer balls is \( 15x \) (since each soccer ball costs $15), and the cost of footballs is \( 20y \) (since each football costs $20).

The athletic director can spend no more than $150, which means the total cost cannot exceed this amount. Therefore, we can express this situation with the inequality:

\[ 15x + 20y \leq 150 \]

Thus, the correct response is:

**15x + 20y ≤ 150**
(15 x plus 20 y is less than or equal to 150)