Question

6. A volleyball player spikes a 0.5 kg volleyball with a force of 12.2 newtons. Assuming no resistive forces are acting on the ball, what is the acceleration of the volleyball to the nearest m/s2? Response area is the volleyball's mass. The force is Response area To find the acceleration, Response area the Response area by the Response area. Final answer, rounded to the nearest tenth is Response area with units of Response area
Answers:
0.5 kg
12.2 n
divide
force
mass
24.4
m/s^2

Answer 1

To find the acceleration of the volleyball, you can use Newton's second law, which states:

\[ F = m \cdot a \]

Where:
- \( F \) is the force applied,
- \( m \) is the mass of the object,
- \( a \) is the acceleration.

Rearranging this formula to solve for acceleration \( a \) gives:

\[ a = \frac{F}{m} \]

Plugging in the values provided:

- The mass \( m = 0.5 \) kg
- The force \( F = 12.2 \) N

Now calculate the acceleration:

\[ a = \frac{12.2 \, \text{N}}{0.5 \, \text{kg}} \]
\[ a = 24.4 \, \text{m/s}^2 \]

So the acceleration of the volleyball is **24.4 m/s²** (rounded to the nearest tenth).

Final answer:
**24.4 m/s²**