Question

A 78 kg volleyball player jumps and leaves the ground with a vertical
velocity of 3.5 m/s. By thinking about the conservation of energy in a
freefalling object, work out how high their centre of mass would reach at
the top of their jump and present your answer to the nearest centimetre.

Answer 1

See for example:

http://en.wikipedia.org/wiki/Coulomb's_law

Answer 2

Oops,wrong post.

Answer 3

m=78kg
v=3.5 m/s
With energy conserved,
PE=KE
mgh=(1/2)mv²
h=v²/(2g)
=3.5²/(2*9.8) m

Convert result to nearest centimetre.