Question

Na2S+2HCl→_____ How many atoms of Na , H , Cl , and S are found in the products of this reaction?

Answer 1

The reaction you've provided is:

\[ \text{Na}_2\text{S} + 2\text{HCl} \rightarrow \text{2NaCl} + \text{H}_2\text{S} \]

Now, let's analyze the products to determine the number of atoms of each element:

1. **Sodium (Na)**: There are 2 Na atoms in the product \( \text{2NaCl} \).
2. **Hydrogen (H)**: There are 2 H atoms in \( \text{H}_2\text{S} \).
3. **Chlorine (Cl)**: There are 2 Cl atoms in \( \text{2NaCl} \).
4. **Sulfur (S)**: There is 1 S atom in \( \text{H}_2\text{S} \).

So, in the products of this reaction, we have:

- **Na**: 2 atoms
- **H**: 2 atoms
- **Cl**: 2 atoms
- **S**: 1 atom