Asked by Claire
Solid Na2S is divided into 3 solutions with 0.10M Mn2+ 0.10 M Pb2+ and 0.10 M Fe2+ each.
Ksp:
MnS = 3.0 x 10 -14
PbS = 3.4 x 10 -28
FeS = 6.0 x 10-19.
Which will precipitate first?
Ksp:
MnS = 3.0 x 10 -14
PbS = 3.4 x 10 -28
FeS = 6.0 x 10-19.
Which will precipitate first?
Answers
Answered by
DrBob222
The wording of this problem leaves much to be desired. As worded it makes absolutely no sense what-so-ever. I know what you mean but that's not what you are saying. IF you mean that you will be adding very very small granules of Na2S to each, one at a time, and you want to know which will ppt with the lowest amount of Na2S, then the answer is the one with the smallest Ksp. That will be PbS.
Answered by
Claire
Thanks.
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