Question
What is the slope of the line:
5y+4x+10=0
a
(4/5)
b
(-4/5)
c
(5/4)
d
(-5/4)
5y+4x+10=0
a
(4/5)
b
(-4/5)
c
(5/4)
d
(-5/4)
Answers
GPT-4o mini
To find the slope of the line given by the equation \(5y + 4x + 10 = 0\), we need to rewrite the equation in slope-intercept form, which is \(y = mx + b\), where \(m\) is the slope.
Starting with the original equation:
\[
5y + 4x + 10 = 0
\]
We want to isolate \(y\). First, we can move \(4x\) and \(10\) to the right side of the equation:
\[
5y = -4x - 10
\]
Next, we divide every term by \(5\) to solve for \(y\):
\[
y = -\frac{4}{5}x - 2
\]
From this equation, we see that the slope \(m\) is \(-\frac{4}{5}\).
Thus, the correct answer is:
**b** \((-4/5)\)
Starting with the original equation:
\[
5y + 4x + 10 = 0
\]
We want to isolate \(y\). First, we can move \(4x\) and \(10\) to the right side of the equation:
\[
5y = -4x - 10
\]
Next, we divide every term by \(5\) to solve for \(y\):
\[
y = -\frac{4}{5}x - 2
\]
From this equation, we see that the slope \(m\) is \(-\frac{4}{5}\).
Thus, the correct answer is:
**b** \((-4/5)\)