what is the efficiency of a ramp if 2,000 joules of energy results in 1,200 joules of work? (show your work)

1 answer

To calculate the efficiency of a ramp, we can use the formula for efficiency, which is given by:

\[ \text{Efficiency} (%) = \left( \frac{\text{Useful Work Output}}{\text{Total Energy Input}} \right) \times 100 \]

In this case, the useful work output is 1,200 joules, and the total energy input is 2,000 joules.

Now, plug in the values:

\[ \text{Efficiency} (%) = \left( \frac{1,200 , \text{joules}}{2,000 , \text{joules}} \right) \times 100 \]

Calculating the fraction:

\[ \frac{1,200}{2,000} = 0.6 \]

Now multiply by 100 to get the percentage:

\[ \text{Efficiency} (%) = 0.6 \times 100 = 60% \]

Therefore, the efficiency of the ramp is 60%.