Question
What is the efficiency of a block and tackle that lifts a 500N resistance a height of 1m when an effort of 80N moves through a distance of 10m? What is the input work? output work?
Answers
drwls
Input work = 80*10 = 800 J
Output work = 500*1 = 500 J
Efficiency = (output)/(input)
= 5/8 = 62.5%
Output work = 500*1 = 500 J
Efficiency = (output)/(input)
= 5/8 = 62.5%